Underground Shaft Hoisting Capacity

How long a hoist cycle takes, the skip payload your production needs, and what that asks of the rope and the motor.
Production skip hoisting up a vertical shaft only: one hoist, one compartment. It is not a hoist design, not a headframe or shaft-furnishing design, not a brake or duty-cycle calculation, and it does not size a cage for people. Hoisting is statutory ground: rope safety factors, speeds and accelerations are set by your regulator and your hoist engineer, not by this page.

A mine skip being hoisted in a vertical shaft, headframe sheaves above

Step 1: The hoist

Speed only helps if the shaft is deep enough to reach it.

Step 2: The production it has to carry

Payload is whatever the tonnage divided by the cycles leaves you.

Step 3: Skip and rope

Two books give two different skip tare rules. Both are here.

The rope is picked for you, and it is the smallest one that works. Step 7 of the published procedure says to select a rope with the required strength, so this page walks Table 12.23 in size order and takes the first that meets it. Step 8 then adds the weight of that rope hanging in the shaft and re-checks the safety factor, which is the check the rope's own weight can fail on a deep shaft.

Step 4: Checks

Published bands. Outside them you are past what the sources cover.

QuantityPublished rangeYours
Maximum hoisting speed
typical published range
2 to 20 m/s12.00
Acceleration
as high as 1.2, typically 0.75
up to 1.2 m/s²0.75
Deceleration
as high as 1.2, typically 0.75
up to 1.2 m/s²0.75
Rope safety factor
four to ten are common
4 to 108.50

Speeds, accelerations and the 20 s load-and-dump time are all from SME Mining Reference Handbook 1st ed. p. 238. The handbook adds that mining laws and regulations may place their own limits on maximum accelerations and speeds, and those outrank anything here.

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skip payload needed
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hoist cycle time
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motor power
StepValueWhere it comes from

Where the cycle goes

What more speed buys

The published selection procedure
StepWhat the handbook saysOn this page
4Use the required annual production and available hoisting times per year to calculate the skip payload.done
5Use the skip payload and a reasonable skip tare mass based on 70% of the skip payload to determine the total attached load.done, and the competing Eq. 12.44 rule is offered beside it
6Multiply the attached load by 8.5 to determine the required rope strength.done
7Select a rope with this strength.done, from Table 12.23 p. 316: the smallest published size that meets it
8Check that the rope strength also meets the required safety factor (typically 5) when the rope weight is added.done, using that rope's published kg/m over the hoisting distance
9Determine the drum diameter based on 80:1 drum-to-rope diameter.done
10Estimate the motor power using kW = (payload × speed)/102.done
11Estimate the inertia of the rotating parts based on historical data.not done: needs the machine
12Carry out a duty cycle calculation to verify the selection.not done: needs the machine

SME Mining Engineering Handbook, selection procedure for production drum hoists, p. 1300. Steps 11 and 12 are inertia from historical data and a full duty-cycle calculation; both need the machine, not the shaft, and neither is attempted here.

For a Koepe or friction hoist the same page says the procedure is identical except that the number of ropes must be defined, four being a reasonable starting point, and that the conveyances must be heavy enough to keep the tension ratio between the loaded and empty sides below about 1.5. It also caps the coefficient of friction used in that calculation at 0.25, which it says is achievable even with wet ropes as long as they are not overlubricated. This page sizes a drum hoist and does not attempt the T₁/T₂ check.

The cycle time equation

SME Mining Reference Handbook 1st ed. p. 238, Equation 12.43 after Edwards 1992:

TCH = (Vmax/ACC) + (H/Vmax) − [(Vmax/2)(1/ACC + 1/RET)] + (Vmax/RET) + Tdl

where TCH is cycle time in seconds, H the hoisting distance, Vmax the maximum speed, ACC and RET the acceleration and retardation, and Tdl the combined load and dump time. The printed note adds that for a single-skip system you get the time to lower the empty skip by excluding Tdl.

That equation is the ordinary trapezoidal speed profile written in one line, and it can be checked rather than trusted: accelerate to speed, run at speed, decelerate, add the load and dump. Worked both ways for an 800 m lift at 12 m/s and 0.75 m/s², the equation and the physics agree to the millisecond, which is a stronger statement about the transcription than any number-matching could make.

What this tool does not know. It sizes the duty, not the machine. It does not calculate the inertia of the rotating parts, does not run the duty cycle that verifies the motor and the brakes, and does not check rope life, sheave sizing, headframe clearance, rope stretch or the harmonic behavior of the flight rope, all of which the handbook treats at length. It assumes a single skip in balanced hoisting and does not model a counterweight, a clutched double drum, or hoisting from several levels. It says nothing about people or materials movement, which competes for the same shaft. Every published value has been checked against the printed page.

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Worked example

Worked with the values this page loads with, so the method can be checked against the cited source without entering anything. Change any input above and the calculator recomputes; the numbers below stay as a fixed reference case.

Hoisting distance800 myour input
Maximum speed12.00 m/syour input; published range 2 to 20 m/s
Distance to reach speed and stop192 mV²/2ACC + V²/2RET; must fit in the shaft
Accelerate to speed16.0 sEq. 12.43 p. 238
+ run and decelerate66.7 sEq. 12.43 p. 238
+ load and dump20.0 syour input; about 20 s is typical, p. 238
= hoist cycle time102.7 sEq. 12.43 p. 238
= cycles per hour35.13,600 ÷ cycle time
Annual production2000000 t/yyour input
÷ available hoisting hours6000 h/yyour input
× operating efficiency× 0.70published average for hoists is 0.7, p. 238
= skip payload13.58 tstep 4, selection procedure p. 1300
Skip tare, 70% rule9.51 tstep 5, selection procedure p. 1300
Skip tare, Eq. 12.447.47 t0.5 × payload + 680 kg, p. 238
= tare in use9.51 tthe 70% rule
= total attached load23.09 tpayload + tare, step 5
× rope strength factor× 8.5step 6 uses 8.5, selection procedure p. 1300
= required rope strength196.23 t forcestep 6, selection procedure p. 1300
= smallest rope that meets it54 mmstep 7; 18 × 7 Independent Wire Rope Core Sinking (round), Table 12.23 p. 316
its published strength197.25 t forceTable 12.23 p. 316
its weight over 800 m9.75 t12.19 kg/m × 800 m, Table 12.23
= safety factor with rope weight6.01step 8; strength ÷ (attached load + rope weight)
= drum diameter at 80:14.32 mstep 9 on the selected rope, selection procedure p. 1300
= motor power1598 kWpayload kg × 12.00 m/s ÷ 102, step 10, selection procedure p. 1300
= hoisting capacity333 t/hpayload × cycles per hour × efficiency

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